x^2+17x+50=0

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Solution for x^2+17x+50=0 equation: 



x^2+17x+50=0

a = 1; b = 17; c = +50;
Δ = b2-4ac
Δ = 172-4·1·50
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{89}}{2*1}=\frac{-17-\sqrt{89}}{2}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{89}}{2*1}=\frac{-17+\sqrt{89}}{2}
$

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